Saturday, May 23, 2009

Chapter 3 Question 11

Matches contain potassium chlorate (V), KClO3. On heating, potassium chlorate (V) decomposes to form potassium chloride and oxygen gas which supports combustion of the matches. Calculate the volume of oxygen gas released at room temperature and pressure when 2.45 g of potassium chlorate (V) is heated. (R.A.M: O, 16; Cl, 35.5; K, 39; 1 mol of gas occupies 24 dm^3 at room temperature and pressure)

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